* What should be convention C?
@ 2014-07-24 16:34 Victor Porton
2014-07-24 16:50 ` Niklas Holsti
0 siblings, 1 reply; 2+ messages in thread
From: Victor Porton @ 2014-07-24 16:34 UTC (permalink / raw)
Suppose we need to interface a procedure C_Procedure which receives a
pointer to a record C_Record.
Is Convention=>C needed for both of the below? Or just to one (which?)
type C_Record is
record
A: unsigned;
B: unsigned;
end record
with Convention=>C;
procedure C_Procedure(X: access C_Record)
with Convention=>C;
--
Victor Porton - http://portonvictor.org
^ permalink raw reply [flat|nested] 2+ messages in thread
* Re: What should be convention C?
2014-07-24 16:34 What should be convention C? Victor Porton
@ 2014-07-24 16:50 ` Niklas Holsti
0 siblings, 0 replies; 2+ messages in thread
From: Niklas Holsti @ 2014-07-24 16:50 UTC (permalink / raw)
On 14-07-24 19:34 , Victor Porton wrote:
> Suppose we need to interface a procedure C_Procedure which receives a
> pointer to a record C_Record.
>
> Is Convention=>C needed for both of the below? Or just to one (which?)
Both.
> type C_Record is
> record
> A: unsigned;
> B: unsigned;
> end record
> with Convention=>C;
>
> procedure C_Procedure(X: access C_Record)
> with Convention=>C;
In order to link with C_Procedure, you must Import C_Procedure.
In order to ensure use the C calling convention, you must specify
Convention(C) for C_Procedure.
RM B.1(26/3) then says that the result and parameter types of
C_Procedure must be "compatible" with Convention(C).
RM B.1(12) and its sub-bullets then say, essentially, that Comvention(C)
must be specified for the result and parameter types, thus for C_Record,
unless the implementation somehow implicitly permits C_Record as
compatible with Convention(C), on which one should not rely.
--
Niklas Holsti
Tidorum Ltd
niklas holsti tidorum fi
. @ .
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